6x^2+96x-13=-13

Solution for 6x^2+96x-13=-13 equation:

6x^2+96x-13=-13

We move all terms to the left:

6x^2+96x-13-(-13)=0

We add all the numbers together, and all the variables

6x^2+96x=0

a = 6; b = 96; c = 0;
Δ = b2-4ac
Δ = 962-4·6·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-96}{2*6}=\frac{-192}{12}
=-16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+96}{2*6}=\frac{0}{12}
=0
$